Elitmus
Exam
Numerical Ability
Log and Antilog
two sides of triangle are 50m and 8m, third side is n, find out the n??
a)392 b)390 c) 398 d) 395
Read Solution (Total 9)
-
- Two sides of triangle are ln(50) and ln(8), third side is ln(n). Find out the number of possible values of n?
Ans:-
Sum of two sides of a triange is always greater than the third side
case 1:
So, ln(50) + ln(8) > ln(n)
=> ln(50x8) > ln(n) ( ∵ log (a) + log(b) = log(ab) )
=> 400 > n
i.e. n < 400
logax is defined for x > 0. So, n will be greater than 0
So, 0 < n < 400
case 2:
So, ln(50) + ln(n) > ln(8)
=> ln(50n) > ln(8) ( ∵ log (a) + log(b) = log(ab) )
=> 50n > 8
i.e. n > 4/25
case 3:
So, ln(8) + ln(n) > ln(50)
=> ln(8n) > ln(50) ( ∵ log (a) + log(b) = log(ab) )
=> 8n > 50
i.e. n > 25/4
Combining results from case 1, case 2 and case 3 we get:
25/4 < n < 400
So, range of integral values of n satisfying the above condition is: 7 ≦ n ≦ 400
Hence no of integral values of n are: 393 - 9 years agoHelpfull: Yes(13) No(0)
- wrong question
- 9 years agoHelpfull: Yes(7) No(2)
- question is
two sides of triangle are ln(50) and ln(8), third side is ln(n), find out the n??
a)392 b)390 c) 398 d) 395 - 9 years agoHelpfull: Yes(2) No(1)
- @ashok how can u write 393 as ans.??
- 9 years agoHelpfull: Yes(2) No(0)
- Incomplete Question.Please upload again
- 9 years agoHelpfull: Yes(1) No(0)
- difference of two sides< 3rd side< sum of two sides
sum=ln(50)+ln(8)=ln(400)
difference=ln(50)-ln(8)=ln(25/4)=ln(6.2)
so, ln(6.2) - 8 years agoHelpfull: Yes(1) No(0)
- the answer would be 392
the range would be from 25/4 to 400 25/4 - 7 years agoHelpfull: Yes(1) No(0)
- please submit appropriate answer
- 7 years agoHelpfull: Yes(1) No(0)
- Plz give the solution..
- 9 years agoHelpfull: Yes(0) No(0)
Elitmus Other Question