Elitmus
Exam
Numerical Ability
Time Distance and Speed
a goes to place x and b goes to place y.
after a travelled 180 km more than b they together meet at a point between xy. they together had their lunch for half an hour. after that a took 2 hrs to reach x and b took 4.5 hrs to reach y. find distance between x and y?
a)900km b)540km c)720km d) not remember
Read Solution (Total 6)
-
- let speed of A be-------Sa
let speed of B be--------Sb
let the distance covered by B while going to position XY be-----------x
so distance covered by A in same time while going to XY is----------180 +x(it's given in the question)
so total distance b/w X and Y is=x+(x+180)
while going to position XY :-
time taken by A = time taken by B
(x+180)/Sa= x/Sb
Sa/Sb=(x+180)/x---------------------1
after lunch:-
A.C.T(according to question)
Sa=x/2
Sb=(x+180)/4.5
dividing Sa/Sb=(x*4.5) / ((x+180)*2)--------------------2
equating equations 1 and 2
9/4 = (x+180)^2 / x^2
now taking square root on both sides we get
3/2 = (x+180) / x
x=360
therefore distance between x and y =x+(x+180)=900km
option A is correct - 9 years agoHelpfull: Yes(18) No(1)
- answer is 900
at the meeting point time is constant
s1/s2= D1/D2
solving by option taking 900
s1/s2=540/360=3/2 .............. (1)
it means a have to travel 360 km in 2 hrs speed of a= 180 kmph
by eq(1) speed of b is 120kmph and it will take 4.5 hrs to travel 560 km.
thus 900 kn is answer - 9 years agoHelpfull: Yes(10) No(10)
- condition for velocity is missing
- 9 years agoHelpfull: Yes(3) No(4)
- ans is 540 km
let speed of A be-------Sa
let speed of B be--------Sb
let the distance covered by B while going to position XY be-----------x
so distance covered by A in same time while going to XY is----------180 +x(it's given in the question)
so total distance b/w X and Y is=x+(x+180)
while going to position XY :-
time taken by A = time taken by B
(x+180)/Sa= x/Sb
Sa/Sb=(x+180)/x---------------------1
after lunch:-
A.C.T(according to question)
Sa=x/2
Sb=(x+180)/4.5
dividing Sa/Sb=(x*4.5) / ((x+180)*2)--------------------2
equating equations 1 and 2
9/4 = (x+180)^2 / x^2
now taking square root on both sides we get
3/2 = (x+180) / x
so ,x =180
and total distance is = x+(x+180)=540 km
- 9 years agoHelpfull: Yes(2) No(6)
- 180 km wil tak 2.5 hr
ans 468 - 9 years agoHelpfull: Yes(0) No(6)
- 180 km in 2.5hr ,speed of b will become=72km/h
sa=1.5*72 =108 km/h
total dist=540km
- 9 years agoHelpfull: Yes(0) No(6)
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