Elitmus
Exam
Numerical Ability
Log and Antilog
in a triangle sides of triangle are ac=ln(n),
ab=ln(8),bc=ln(50).
what is the possible value of n?
Read Solution (Total 8)
-
- sum of 2sides of the triangle should be greater than the third side
therefore,ln(50)+ln(8)>ln(n)
Now according to the log property;log(a)+log(b)=log(a*b)
So,ln(50*8)>ln(n)
400>n;
Bt the options are;
390,395,392and 398.
So 0 and 400 wont be included,so the ans is 398.
- 9 years agoHelpfull: Yes(8) No(2)
- Sum of two sides of a triange is always greater than the third side
case 1:
So, ln(50) + ln(8) > ln(n)
=> ln(50x8) > ln(n) ( ∵ log (a) + log(b) = log(ab) )
=> 400 > n
i.e. n < 400
logax is defined for x > 0. So, n will be greater than 0
So, 0 < n < 400
case 2:
So, ln(50) + ln(n) > ln(8)
=> ln(50n) > ln(8) ( ∵ log (a) + log(b) = log(ab) )
=> 50n > 8
i.e. n > 4/25
case 3:
So, ln(8) + ln(n) > ln(50)
=> ln(8n) > ln(50) ( ∵ log (a) + log(b) = log(ab) )
=> 8n > 50
i.e. n > 25/4
Combining results from case 1, case 2 and case 3 we get:
25/4 < n < 400
So, range of integral values of n satisfying the above condition is: 7 ≦ n ≦ 400
Hence no of integral values of n are: 393 - 7 years agoHelpfull: Yes(5) No(0)
- apply sum of two side of a triangle is always greater than third side
so ln(n) n - 9 years agoHelpfull: Yes(1) No(3)
- apply sum of two side of a triangle is always greater than third side
get
400>n
but options are given a) 390 b) 395 c) 392 d) 398
what should be right ans???
- 9 years agoHelpfull: Yes(1) No(1)
- Ans will be398.
Becouse 0 and 400 will not be included. - 9 years agoHelpfull: Yes(1) No(1)
- Answer should be b) 392
as this sum of 2 side should be greater than the third side, and it cant be equal
So, it cant take up the value 400
answer = 399 - 7 = 392 - 5 years agoHelpfull: Yes(1) No(0)
- Sum Of two side should be > rest of side (this is the key point)
ln(8)+ln(50)>ln(n)
====>>(using ln(a)+ln(b)=ln(ab))
ln(400)>ln(n)
400>n ------------------------------------------- 1st condition
now ln(8) + ln(n) > ln(50)
8n > 50 (Use of same concept as above)
n > 25/4 --------------------------------------------2nd condition
also include
ln(50) + ln(n) > ln(8)
50n>8
n > 4/25--------------------------------- 3rd condition..
have a look on all condition and try to find out the common term of all condition
(400 > n && n > 25/4 && n > 4/25 )
then we can conclude simply as
25/4 < n < 400
7 - 9 years agoHelpfull: Yes(0) No(0)
- since log a p= log p/log a
log ap(log a/p)/log pa(logp/a)
log ap (log pa)/log pa(log ap)
all the terms get cancelled
Ans will -----1. - 6 years agoHelpfull: Yes(0) No(0)
Elitmus Other Question