if a+b+c = 0
then find out,
a^3+b^3+c^3 -3abc = ?

• we know that
  a^3+b^3+c^3 -3abc = (a+b+c)*(a^2+b^2+c^2-ab-bc-ca)
  
  putting (a+b+c)= 0
  we get, a^3+b^3+c^3 -3abc = 0
• 9 years agoHelpfull: Yes(2) No(0)
• a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2 -ab-bc-ca)
  = 0
  as a+b+c=0
• 9 years agoHelpfull: Yes(1) No(0)
• 0 use the identity a^3+b^3+c^3=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)
• 9 years agoHelpfull: Yes(0) No(0)