IBM
Company
Numerical Ability
Permutation and Combination
25 buses are running between two places P and Q. In how many ways can a person go from P to Q and return by a different bus?
Option
1) 625
2) 600
3) 576
4) None of these
Read Solution (Total 10)
-
- we can go in any bus out of the 25 buses.
Hence He can go in 25 ways.
Since we can not come back in the same bus that he used for travelling,
we can return in 24 ways.
Total number of ways = 25 x 24 = 600 - 9 years agoHelpfull: Yes(53) No(1)
- 25c1*24c1=600
ans will be 600 - 9 years agoHelpfull: Yes(5) No(0)
- There are 25C1 ways to go from pto q and 24c1 ways to come back from q to p.So total=25*24=600
- 9 years agoHelpfull: Yes(4) No(0)
- 25*24=600
goes from P to Q in 25 ways and returns in 24 ways - 9 years agoHelpfull: Yes(3) No(0)
- 25*24=600
so second option will be right because person go from p to q by 25 ways but he return only 24 ways because return bus should not same as going from p to q. - 8 years agoHelpfull: Yes(2) No(0)
- we can go in any bus out of the 25 buses.
Hence He can go in 25 ways.
Since we can not come back in the same bus that he used for travelling,
we can return in 24 ways.
Total number of ways = 25 x 24 = 600 - 8 years agoHelpfull: Yes(1) No(1)
- one side 25 buses
return 25-1 because in this qn mention P to Q and Q to P are different buses so
25*24=600 - 9 years agoHelpfull: Yes(0) No(0)
- 25 ways from P to Q..
without repeatation 24 ways from Q to P
25*24=600 - 9 years agoHelpfull: Yes(0) No(0)
- while running from P to Q = 25 ways
while return from Q to P=24 ways
total=25*24
=600 - 9 years agoHelpfull: Yes(0) No(0)
- NO of possibilities =25^2=625
- 9 years agoHelpfull: Yes(0) No(9)
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