A pipe takes a hours to fill the tank. But because of a leakage it took 3 times of its original time. Find the time taken by the leakage to empty the tank

• ans=90
  pipe a can do a work 60 min.
  lets leakage time is x;
  then
  1/60 -1/x=1/180
  x=90 min(1 hr 30min);
• 9 years agoHelpfull: Yes(9) No(0)
• 1 1/2 hrs.
  
  Filling in 1 hr.=1 & if leakage/hr.=1/L, then 1- (1/L)=1/(1*3)=1/3, 1/L=2/3
  So the time by leakage to empty the tank=3/2=1 1/2 or 1.5 hrs.
• 9 years agoHelpfull: Yes(5) No(0)
• assume dat pipe takes 100 mins to fill the tank.(a=100) -> (1/100)th work done per minute
  because of leakage it takes 3times of original time to fill the tank. -> 300mins
  [1/100]*300 - [1/x]*300 = 1
  by solving for x u can get it as 150 which is equal to (3/2)a
• 9 years agoHelpfull: Yes(0) No(0)
• 1 1/2 hrs. (1 hr 30min)
  
  Filling in 1 hr.=1 & if leakage/hr.=1/L, then 1- (1/L)=1/(1*3)=1/3, 1/L=2/3
  So the time by leakage to empty the tank=3/2=1 1/2 or 1.5 hrs.
• 8 years agoHelpfull: Yes(0) No(0)
• 60
  3:1
  60/4*3=75 min
  1hr:15 min
• 8 years agoHelpfull: Yes(0) No(0)
• (1*3)/ (1-3)= 1.5 hrs
• 6 years agoHelpfull: Yes(0) No(0)