How many words with or without meaning, can be formed by using all the letters of the word, DELHI using each letter exactly once?

Option
1) 720
2) 24
3) None of these
4) 120

• 5!=120 ways bcoz 5letters
• 9 years agoHelpfull: Yes(16) No(0)
• 5! = 5*4*3*2*1 = 120
• 9 years agoHelpfull: Yes(2) No(0)
• delhi contains 5 letters without any repitition of letters.so 5!=120
• 9 years agoHelpfull: Yes(2) No(0)
• 5! =5*4*3*2*1=120
• 9 years agoHelpfull: Yes(2) No(0)
• delhi contains 5 letters without any repitition of letters.so 5!=120
• 9 years agoHelpfull: Yes(1) No(0)
• 5!=120....
• 5 years agoHelpfull: Yes(1) No(0)
• 5!=120 as the condition given is each letter once
• 4 years agoHelpfull: Yes(1) No(0)
• answer is 120
  here it contains 5 letters no same letters so 5|
• 9 years agoHelpfull: Yes(0) No(0)
• plz tell me is their any upcoming drive for 2014 batch in hyderabad tnq in advnc...................
• 9 years agoHelpfull: Yes(0) No(0)
• 5 letters without reputation 5*4*3*2*1=120
• 9 years agoHelpfull: Yes(0) No(0)
• 5!=5*4*3*2*1=120
• 8 years agoHelpfull: Yes(0) No(0)
• DELHI=5 letters
  5! ways =5p5=5*4*3*2*1=120 ways
• 8 years agoHelpfull: Yes(0) No(0)
• DELHI =5 words
  therefore the total words can be formed by using this 5 words =5!=5*4*3*2*1=120
• 8 years agoHelpfull: Yes(0) No(0)
• 5! = 120 is the answer
• 8 years agoHelpfull: Yes(0) No(0)
• 5 letters in delhi so 5!=120
• 8 years agoHelpfull: Yes(0) No(0)
• no.of letters in 'DELHI' is 5
  so, no.of words formed can be, nPr=n!/(n-r)!
  =5!/(5-5)!
  =5!/0!
  =5!=120
• 8 years agoHelpfull: Yes(0) No(0)
• 120 its a 5 factorial
• 8 years agoHelpfull: Yes(0) No(1)
• 5! way we can select the word
• 7 years agoHelpfull: Yes(0) No(0)
• 120
  5!=120
  
• 7 years agoHelpfull: Yes(0) No(0)
• 5!=120 ways bcoz 5letters
• 7 years agoHelpfull: Yes(0) No(1)
• 5!=120 ways
  
• 7 years agoHelpfull: Yes(0) No(0)
• 5!=120 becoz delhi has 5 letters so 120 combinations
• 7 years agoHelpfull: Yes(0) No(0)
• 5!ways
  120
• 7 years agoHelpfull: Yes(0) No(0)
• 120 .5.4.3.2.1
• 5 years agoHelpfull: Yes(0) No(0)