f(x)=(2x^2-5)/(2x^2+1) then f(x)is

• f(x) is between 1 to -5
• 9 years agoHelpfull: Yes(2) No(1)
• f(x) is between 0 to 1
  
• 9 years agoHelpfull: Yes(1) No(1)
• f(x) is between 0 to 1
• 9 years agoHelpfull: Yes(0) No(5)
• expanding (2x^2/ (2x^2+1)) -(5/ (2x^2+1))
  f(x) = 1-(6/ (2x^2+1))
  f(x) = (+-) sqrt(5/2)
• 9 years agoHelpfull: Yes(0) No(1)
• =2x^-3/2X^3
  =(1/2x^3)2X^3
  =1
• 9 years agoHelpfull: Yes(0) No(1)
• for any values of x ie ...........-3,-2,-1,0,1,2,3,............ aplied to above equation the value of f(x) is -5 or 0 or -1.
• 9 years agoHelpfull: Yes(0) No(0)
• f(x) is 0 or -1 or -5 ( for all the substituted values )
• 8 years agoHelpfull: Yes(0) No(0)