state the output of the following code:
intnum=80;
inti=1;
intmul=1;
while(i<=num){
System.out.println(i+" ");
i+=4*mul++;
if(mul%3==0)
++mul;
}

• i=1 prints 1
  i=1+(4*1)=>5 prints 5
  i=5+(4*2)=>13 prints 13
  now mul value =3
  enters if loop ---->increments mul to 4
  i=13+(4*4)=>29 prints 29
  1=29+(4*5)=>49 prints 49
  now mul=6
  enters the loop and increments to 7
  i=49+(4*7)=>77 prints 77
  
  exit the loop
  
• 8 years agoHelpfull: Yes(31) No(0)
• 1
  5
  13
  29
  49
  77
• 9 years agoHelpfull: Yes(17) No(1)
• 1
  5
  13
  25
  41
  61
• 8 years agoHelpfull: Yes(10) No(15)
• datatype and variable should be written seperately, i think this won't compile.
• 9 years agoHelpfull: Yes(6) No(5)
• 1
  5
  13
  29
  49
  77
• 8 years agoHelpfull: Yes(3) No(0)
• As when loop start value of i= 1 and mul =1.
  fistrly 1 will be printed and value of i becomes 5(i= 1+4*1). (mul ++ means post increment firstly it works then change value ). mul%3==0 this condition fails because mul = 2(as mul++) so 2%3 is not equal to zero...
  the process contiues and output will be
  1 5 13 29 49 77
• 7 years agoHelpfull: Yes(3) No(0)
• answer - 1,5,13,29,49,77
• 7 years agoHelpfull: Yes(0) No(0)
• 1+4+8+12+20+24+32=101(mul=4,7 are skipped bcz of ++mul)
• 6 years agoHelpfull: Yes(0) No(0)
• 1,5,13,29,77
• 6 years agoHelpfull: Yes(0) No(0)
• output::
  1
  5
  13
  29
  49
  77
• 6 years agoHelpfull: Yes(0) No(0)
• i | mul
  1 | 1
  5 | 2
  13 | 4
  29 | 5
  49 | 7
  77 | 8
  109 | 10
  while(i
• 6 years agoHelpfull: Yes(0) No(0)