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The salary of A is 20% lower than B's salary and the salary of c is 56.25% greater than A's salary .By how much percentage the salary of B is less than the salary of C?

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20%

A=(100-20)B/100=0.8B ---(i) and
C=(100+56.25)A/100=1.5625A ---(ii)
From (i) & (ii), C=1.5625*0.8B=1.25B or B=C/1.25=0.8C
So salary of B is 20% less than C.
8 years agoHelpfull: Yes(2) No(0)

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