in a class 30% of the student offered english ,20% offered hindi and 10% offered both.if a student is select at random,What is the probablity that he has offered english or hindi?

• Let p(A) = 30% = 0.3
  P(B) = 20% = 0.2
  Both, p(AnB) = 10% = 0.1
  
  So, p(AuB) = p(A)+p(B)-p(AnB)
  P(AuB) = 0.3+0.2-0.1 = 0.4 = 4/10 = 2/5
• 7 years agoHelpfull: Yes(5) No(0)
• 2/5
  
  % offered only english=30-10=20, only hindi=20-10=10 and both english & hind=10
  Here total 20+10+10=40% students has offered either english or hindi
  so same will be probaility of a student, who has offered english or hindi if selected at random,
  Hence probability =40/100=2/5
• 9 years agoHelpfull: Yes(2) No(0)