messy shoots every 3rd penalty to goal. if he gets chance to shoot all five penalty shots. what is the probability that he converts (does) exactly 3 goals.

asked in elitmus 21st september 2014

• probability for goal in 1 shot= 1/3
  probability probability to miss a goal in a shot = 2/3
  therefore probability of exactly 3 goals= 5C3*(1/3)^3*(2/3)^2
  please correct me if i am wrong ...it will be helpful....thanku
• 9 years agoHelpfull: Yes(41) No(0)
• Updated ans: 5C3*(1/3)^3*(2/3)^2
  =10*1/27*4/9
  
• 9 years agoHelpfull: Yes(9) No(0)
• probability that a goal is scored in 1 shot= 1/3
  probability that no goal is scored in a shot = 2/3
  therefore probability of exactly 3 goals= (1/3)^3*(2/3)^2*5!
• 9 years agoHelpfull: Yes(7) No(20)
• answer could be 3/5
• 9 years agoHelpfull: Yes(3) No(3)
• Ans should be 10*(3/5)^3*(2/5)^2
  
• 9 years agoHelpfull: Yes(3) No(2)
• Since the question says every third penalty will be goal and not that 1 of the 3 penalties will be goal, therefore the probability of goal is not 1/3.
  Now since every third penalty is goal therefore no. of 3rd penalties in 5 penalty shootout is 1 (i.e 3rd) therefore ans will be 0.
• 9 years agoHelpfull: Yes(3) No(6)
• choose 3 goal out of 5 i.e 5C3
  now for a goal=1/3
  not goal=2/3
  so....5C3*1/3*2/3
• 9 years agoHelpfull: Yes(0) No(0)
• choose 3 goal out of 5 i.e 5C3
  now for a goal=1/3
  not goal=2/3
  so....5C3*(1/3)^3*(2/3)^2
• 9 years agoHelpfull: Yes(0) No(1)