IBM
Company
Numerical Ability
Sequence and Series
1,2,3,2,4,6,4,8,_____
Read Solution (Total 56)
-
- Divide the series:
1,2,3
2,4,6
4,8,?
so it is 12 - 9 years agoHelpfull: Yes(10) No(3)
- break the series into three portion such that:
(1,2,3),(2,4,6),(4,8,?)
now simply multiply the first set of each number with 2 to get the second set of number
(1*2,2*2,3*2) =(2,4,6)
similarly multiply the second set of each number with 2 to get the third set of number
(2*2,3*2,6*2)=(4,8,12)
so the final answer would be 12.
- 9 years agoHelpfull: Yes(4) No(0)
- 1*1=1, 2*1=2, 3*1=3
1*2=2, 2*2=4, 3*2=6
2*2=4, 4*2=8 6*2=12
ANS:12 - 9 years agoHelpfull: Yes(2) No(0)
- 12
1,2,3--> gap =1
2,4,6--> gap= 1*2=2
4,8,12--> gap=2*2=4 - 9 years agoHelpfull: Yes(2) No(0)
- 1+1=2
2+1=3
3-1=2
2+2=4
4+2=6
4+4=8
8+4=12
- 9 years agoHelpfull: Yes(1) No(1)
- 1+2=3
2+4=6
4+8=12 - 9 years agoHelpfull: Yes(1) No(0)
- answer is 12
the series like this
1,2,3
2,4,6
4,8,12 - 9 years agoHelpfull: Yes(1) No(0)
- 12
there is 3 different series as 1,2,3........2,4,6.....4,8,12... - 9 years agoHelpfull: Yes(1) No(0)
- 12
1+2=3;
2+4=6;
4+8=12; - 9 years agoHelpfull: Yes(1) No(0)
- ANS): 12
- 8 years agoHelpfull: Yes(1) No(0)
- 12
first three series of multiplication of 1,2,4
- 9 years agoHelpfull: Yes(0) No(2)
- The answer is 12.
first 1,it doudles at 3rd position next to 1..
likewise 6 doubles to give 12 - 9 years agoHelpfull: Yes(0) No(0)
- ans:12
1*1=1
1*2=2
1*3=3 i.e 1,2,3 are multiples of 1
2*1=2
2*2=4
2*3=6 i.e 2,4,6 are multiples of 2
4*1=4
4*2=8
4*3=12 i.e 4,8,12 are multiples of 4 - 9 years agoHelpfull: Yes(0) No(0)
- 1+1=2
2+1=3
3-1=2
2+2=4
4+2=6
6-2=4
4+4=8
8+4=12 - 9 years agoHelpfull: Yes(0) No(0)
- 12. 1,2,3 - 1 table. 2,4,6-2 table, similarly 4,8,12.
- 9 years agoHelpfull: Yes(0) No(0)
- (1,2,3),(2,4,6),(4,8,_)
Answer is 16 - 9 years agoHelpfull: Yes(0) No(0)
- Add 1to the next two series and subtract 1 and repeat for 2 and subtract 2 then adding 4to 4then 8 to 4=12
1+1=2,2+1=3,3-1=2,2+2=4,4+2=6,6-2=4,4+4=8,8+4=12 is answer - 9 years agoHelpfull: Yes(0) No(0)
- 12 b'coz 1+2=3,2+4=6,nd 4+8=12
- 9 years agoHelpfull: Yes(0) No(0)
- Group first 3 terms ( 1 2 3 ) 1+2=3 then next 3 terms(2 4 6) 2+4=6 then next 3 terms (4 8 ?) 4+8=12 so,ans=12
- 9 years agoHelpfull: Yes(0) No(0)
- 1+2=3
2+4=6
4+8=12 - 9 years agoHelpfull: Yes(0) No(0)
- 1+2=3
2+4=6
4+8=12
- 9 years agoHelpfull: Yes(0) No(0)
- first 3 numbers are series
second 3 are multiply 2 with 1st series
1*2=2 2*2=4 3*2=6
6*2=12
- 9 years agoHelpfull: Yes(0) No(0)
- the answer is 12
- 9 years agoHelpfull: Yes(0) No(0)
- 12
1*1=1;1*2=2;1*3=3
2*1=2;2*2=4;2*3=6
4*1=4;4*2=8;4*3=12 - 9 years agoHelpfull: Yes(0) No(0)
- 1st 3 diff is 1
2nd 3 no. diff 2
3rd 3 no diff is 2
ans:12 - 9 years agoHelpfull: Yes(0) No(0)
- the series is in the form +1,+1,-1,+2,+2,-2,+4,+4,-4
- 9 years agoHelpfull: Yes(0) No(0)
- 12(4+8=12)
- 9 years agoHelpfull: Yes(0) No(0)
- 1*2,1*2,1*3,2*1,2*2,2*3,4*1,4*2,4*3 thats why ans is 12
- 9 years agoHelpfull: Yes(0) No(0)
- 1*1,2*1,3*1=1,2,3
1*2,2*2,3*2=2,4,6
1*4,2*4,3*4=4,8,12
- 9 years agoHelpfull: Yes(0) No(0)
- 12
make group of 3
1 2 3
2 4 6
4 8 12 - 9 years agoHelpfull: Yes(0) No(0)
- 1*2=2
2*2=4
3*2=6
2*2=4
4*2=8
6*2=12
- 9 years agoHelpfull: Yes(0) No(0)
- 12
1 2 3
1*2 =2 2*2=4 3*2=6
2*2 4*2 6*2=12
- 9 years agoHelpfull: Yes(0) No(0)
- ans is 12
1 2 3
2 4 6
4 8 12
like that 3 different series
- 9 years agoHelpfull: Yes(0) No(0)
- Divide the series in grps of 3:
1,2,3: 2,4,6; 4,8,12; - 9 years agoHelpfull: Yes(0) No(0)
- 1,2,3->1*2,2*2,3*2=2,4,6
similarly ans is 12 - 9 years agoHelpfull: Yes(0) No(0)
- 1+2=3 ,third number
2+4=6 ,sixth number
4+8=12. answer - 9 years agoHelpfull: Yes(0) No(0)
- 1,2,3
2,4,6
4,8,12 - 9 years agoHelpfull: Yes(0) No(0)
- 12
1x1=1
1x2=2
1x3=3
2x1=2
2x2=2.....so on
so 4x3=12
- 9 years agoHelpfull: Yes(0) No(1)
- ans is 12
1+2=3
2+4-=6
4+8=12
adding 1st 2 nos gives 3rd no....adding 4th and 5th gives 6th no..... - 9 years agoHelpfull: Yes(0) No(1)
- 12
1,2,3,1*2,2*2,3*2,2*2,4*2,6*2 - 9 years agoHelpfull: Yes(0) No(1)
- 1,2,3
2,4,6
4,8,12 - 9 years agoHelpfull: Yes(0) No(1)
- 3*2=6,6*2=12
- 9 years agoHelpfull: Yes(0) No(1)
- ans 12
1 2 3 2*1,2*2,2*3,4*1,4*2,4*3 - 9 years agoHelpfull: Yes(0) No(1)
- 1+2=3,2+4=6,4+8=12
- 9 years agoHelpfull: Yes(0) No(1)
- (1,2,3) dif=1
(2,4,6) dif=2
(4,8,__) dif=4 therefore ans=12 - 9 years agoHelpfull: Yes(0) No(1)
- 12
2*1=2
2*2=4
2*3=6
similarly
4*1=4
4*2=8
4*3=12 will be the answer - 9 years agoHelpfull: Yes(0) No(1)
- 1*2=2,2*2=4,3*2=6,2*2=4,4*2=8,6*2=12 so ans =12
- 9 years agoHelpfull: Yes(0) No(0)
- create group of 3 i.e. (1,2,3),(2,4,6),(4,8,?) so in each group 2nd and 3rd is multiple of first term
so 1*2 = 2
1*3 = 3
and
2*2 = 4
2*3 = 6
so
4*2 = 8
4*3 = 12
so ans is 12;
- 9 years agoHelpfull: Yes(0) No(0)
- take first three numbers
1+2=3
2+4=6
4+8=12
ans is 12 - 9 years agoHelpfull: Yes(0) No(0)
- 1,2,3 difference is 1 1 -1
2 4 6 diff is 2 2 -2
8 12 8 diff should be 4 4 -4 - 8 years agoHelpfull: Yes(0) No(1)
- 12
consider 3 number as group
- 8 years agoHelpfull: Yes(0) No(0)
- The given sequence of numbers is actually made by joining 3 series like shown below.
First Series is formed by = 1st number, 4th number, 7th number
Second Series is formed by = 2nd number, 5th number , 8th number
Third Series is formed by = 3rd number, 6th number, 9th number
So the three series would look like:
1, 2, 4
2, 4, 8
3, 6, ?
Next number for each series is = 2 * previous number.
Hence for 3rd series 6*2 = 12 - 8 years agoHelpfull: Yes(0) No(0)
- 12, the series is 1,2,3,2,4,6,4,8,---,left 1 consider second and third terms 2,3 again fourth term is same as second ,fifth term is twice the second , sixth term is twice the third ,seventh term repeated as same as fifth term like that
- 8 years agoHelpfull: Yes(0) No(0)
- 1,1+1,2+1,3-1,2+2,4+2,6-2,4+4,8+4=12
Ans:12 - 8 years agoHelpfull: Yes(0) No(0)
- series in form of 1,2,3 then 1*2=2, 2*2=4, 3*2=6 then 2*2=4, 4*2=8, and next will be 6*2=12
- 8 years agoHelpfull: Yes(0) No(0)
- 1+1=2
2+1=3
3-1=2
2+2=4
4+2=6
6+2=8
8-2=6 - 8 years agoHelpfull: Yes(0) No(0)
IBM Other Question