A contractor decided to complete the work in 40 days & employed 60 men at the beginning & 40 men additionally after 10 days & got the work completed as per schedule. If he had not employed the additional men, how many extra days would he have needed to complete the work ?

• letus take one man one day work 1/x then 60 men one day work60/x
  for 10 days it will be 10*60/x=600/x
  remaining 30 days 100 men worked so 30*100/x=3000/x
  600/x+3000/x=1==>3600/x=1==>x=3600
  3600 men complete the work in one day
  for 60 men 40 days work is 60*40/3600=2/3
  remaining work is 1-2/3=1/3
  40 days 2/3
  ?days 1/3
  by solving we get 20 days
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