two urns contain respectively 2 red 3 white and 3 red,5 white balls.One ball is drawn at random from the first urn and transferred into the second.A ball is now drawn from the second urn and it turns out to be red.What is the probability that the transferred ball was white?

• according to baye,s theorem
  p(no of way to drawn a ball from 2nd urns is red and ball transferred from 1 urns)=(3c1/5c1)*(3c1/9c1)=9/45
  total=(2c1/5c1)*(4c1/9c1)+(3c1/5c1)*(3c1/9c1)=17/45
  so probablity=9/45/17/45=9/17;
• 9 years agoHelpfull: Yes(10) No(2)
• Sorry Pratibha...Correct answer is 9/17
• 9 years agoHelpfull: Yes(8) No(1)
• 3C1/5C1=3/5
• 9 years agoHelpfull: Yes(3) No(9)
• when ball transfered from 1st urn is red, no of red and white balls in 2nd urn is 4 & 5 respectively.
  if ball transferrd is white , then no of red and white balls is 3 & 6 respectively.
  probability of drawing red ball is(4/9+3/9)=7/9
  according to bayes theorem, probability that transferd ball is white=(3/9)/(7/9)=3/7
  so, answer=3/7
  
• 9 years agoHelpfull: Yes(2) No(4)
• red=2/5
  then second red=3/8
  total=3/8+2/5
  31/40
  ans=1-31/40=9/40
  
• 9 years agoHelpfull: Yes(1) No(8)
• 3/5
  i think if ball is drawn from the second urn it doesnt mattr the first urn its probability remain same
  
• 9 years agoHelpfull: Yes(1) No(4)
• P(transferring white ball) =3/5
  After transfer we will have 3 red and 6 white balls in 2nd urn.
  P(selecting red ball) = 3/9= 1/3
  P(both events happening) = 3/5* 1/3 = 1/5
• 9 years agoHelpfull: Yes(0) No(6)