if a man buys 1 ltr of milk for Rs.12 and mixes it with 20% water and sells it for Rs.15, then what is the percentage of gain?

• 25%
  
  After adding 20% water in milk, the selling quantity becomes 1.2 liters, which has cost price of 12 Rs.
  So % gain=100*(15-12)/12=25
  
  * As it is not mentioned in above example, the mixture is sold @ 15 Rs. per liter, so irrespective of the % of added water, it becomes simply a transaction of CP=12 and SP=15.
• 8 years agoHelpfull: Yes(16) No(7)
• Aftr mixing with water.totall volume =1.2 lit
  1.2 lit costing=12
  1 lit. ". =12/1.2=10 rs
  Gain%=((15-10)/10)*100
  =50%
• 8 years agoHelpfull: Yes(5) No(16)
• i dont know
• 6 years agoHelpfull: Yes(2) No(0)
• 2 cases possible for this question::
  CASE 1: He sells whole of the 1.2L for Rs 15
  He makes a profit of 15-12 = Rs. 3 total with the Cost Price of Rs. 12 . Hence profit% is 3/12*100 = 25% profit.
  
  CASE 2: He sells the mixture at for Rs 15 per Litre
  His total revenue is 15*1.2 = Rs. 18 Hence Profit=18-12= Rs.6 . Hence Profit%= 6/12*100=50% Profit.
• 6 years agoHelpfull: Yes(2) No(0)
• C,P = 12
  new S.P = 15 per litre
  new quantity = 1.2L = 1L milk + .2L water
  S.P = 1.2*15 = 18 Rs
  Profit = 18-12 = 6
  % = 6/12 = 50 %
  
• 8 years agoHelpfull: Yes(1) No(1)
• I agree with devendra marghade
• 8 years agoHelpfull: Yes(1) No(2)
• 15+(20/100)*15=18
  18-12=6
  (6/12)*100=50%
• 8 years agoHelpfull: Yes(1) No(0)
• Since the man gains here , we will looking for more profit rather than digging into the question.
  1.2 lit will cost ₹12 so 1 lit will cost ₹10 .
  and he sells it for ₹15. So there is a profit of ₹5. Hence the percentage of profit is (5/12)*100 = 41.66%
• 7 years agoHelpfull: Yes(1) No(0)
• All values is square expect 17
• 8 years agoHelpfull: Yes(0) No(3)
• 50% is the answer
• 8 years agoHelpfull: Yes(0) No(0)