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if a man buys 1 ltr of milk for Rs.12 and mixes it with 20% water and sells it for Rs.15, then what is the percentage of gain?
Read Solution (Total 10)
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- 25%
After adding 20% water in milk, the selling quantity becomes 1.2 liters, which has cost price of 12 Rs.
So % gain=100*(15-12)/12=25
* As it is not mentioned in above example, the mixture is sold @ 15 Rs. per liter, so irrespective of the % of added water, it becomes simply a transaction of CP=12 and SP=15. - 9 years agoHelpfull: Yes(16) No(7)
- Aftr mixing with water.totall volume =1.2 lit
1.2 lit costing=12
1 lit. ". =12/1.2=10 rs
Gain%=((15-10)/10)*100
=50% - 9 years agoHelpfull: Yes(5) No(16)
- i dont know
- 7 years agoHelpfull: Yes(2) No(0)
- 2 cases possible for this question::
CASE 1: He sells whole of the 1.2L for Rs 15
He makes a profit of 15-12 = Rs. 3 total with the Cost Price of Rs. 12 . Hence profit% is 3/12*100 = 25% profit.
CASE 2: He sells the mixture at for Rs 15 per Litre
His total revenue is 15*1.2 = Rs. 18 Hence Profit=18-12= Rs.6 . Hence Profit%= 6/12*100=50% Profit. - 6 years agoHelpfull: Yes(2) No(0)
- C,P = 12
new S.P = 15 per litre
new quantity = 1.2L = 1L milk + .2L water
S.P = 1.2*15 = 18 Rs
Profit = 18-12 = 6
% = 6/12 = 50 %
- 9 years agoHelpfull: Yes(1) No(1)
- I agree with devendra marghade
- 9 years agoHelpfull: Yes(1) No(2)
- 15+(20/100)*15=18
18-12=6
(6/12)*100=50% - 9 years agoHelpfull: Yes(1) No(0)
- Since the man gains here , we will looking for more profit rather than digging into the question.
1.2 lit will cost ₹12 so 1 lit will cost ₹10 .
and he sells it for ₹15. So there is a profit of ₹5. Hence the percentage of profit is (5/12)*100 = 41.66% - 8 years agoHelpfull: Yes(1) No(0)
- All values is square expect 17
- 9 years agoHelpfull: Yes(0) No(3)
- 50% is the answer
- 9 years agoHelpfull: Yes(0) No(0)
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