if x/y=6/5,then find the value of (x^2+y^2)/(x^2-y^2)

• 61/11
  
  (x^2+Y^2)/(x^2-y^2)=(1/x^2)*[ 1+(y/x)^2] / (1/x^2)*[1- (y/x)^2]
  =[1+(5/6)^2]/[1-(5/6)^2]
  =[1+(25/36)]/[1-(25/36)]
  =61/11
• 8 years agoHelpfull: Yes(2) No(0)
• (36+25)/(36-25)=6.7
• 8 years agoHelpfull: Yes(1) No(4)
• x/y=6/5 ==>x=6;y=5;==>ans:61/11
• 8 years agoHelpfull: Yes(1) No(0)
• Ans : 61/11
  we have to divide y^2 to both numerator and denominator so equestion become ((x/y)^2+1)%((x/y)^2-1)
  and put the value x/y=6/5 so ans will come as 61/11
• 8 years agoHelpfull: Yes(0) No(0)
• x/y=6/5 making both side sqaure it converts as 36/25 now using this 36+25/36-25=61/11
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