int i=5,j; j=i++ + ++i +i++; ans??

• i=5
  So j = (i++) + (++i) + (i++) i ++ means postfix. Initially it wont change. After the operation only value will change to value +1 . ++i means prefix. Value will change to value +1 before operation
  = 5 + (6+1) + (7)
  = 19
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• 20(j=5++ + ++5 + 5++ =(5+7+7)++=19++=20)
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• ans is 19. 32 bit compiler then start calculation from right to left.5+7+7=19
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