Elitmus
Exam
Numerical Ability
Geometry
in an obtuse- angled triangle abc , angle a is the obtuse angle and o is the orthocentre . if angle boc=54 degree ,then angle bac is ?
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- Ans: 126
Solution: Orthocentre of an Obtuse angled triangle remains outside of the angle. It is drawn by extending the sides of triangle... So that we can draw perpendicular to each side from the opposite vertex.
Now say, the perpendicular from vertex 'b' to the extended side 'bc' cuts 'bc' at point 'd'
and the perpendicular from vertex 'c' to the extended side 'ba' cuts at point 'e'
then points a,d,o,e make a quadrilateral, and the angle of doe is 54(as given), aeo=ado=90
so, andle dae= 360-(90+90+54)= 126
now, angle bac= dae (vertically opposite angle)
so, angle of bac is 126
I hope this is the right ans............... :) if not pls reply - 9 years agoHelpfull: Yes(29) No(3)
- When its the case of orthocentre its a property that
angle at centre + angle =180. - 9 years agoHelpfull: Yes(4) No(0)
- by properties of orthocenter
- 9 years agoHelpfull: Yes(0) No(4)
- ya vaku u r right
- 9 years agoHelpfull: Yes(0) No(0)
now according to theorem angle mae by obtuse angel - 9 years agoHelpfull: Yes(0) No(0)
- 108 degree as BC is common segment,if it makes an angle of 54 at the center with BC segment ,it has to be double on the circumference
- 7 years agoHelpfull: Yes(0) No(0)
- angle BOC=54,ANGLE BAC=? PROPERTIES "O" IS ORTHOCENTRE OF TRIANGLE ABC, SO,
ANGLE BOC=180-A, A=54, SAME GOES TO ANGLE BAC=180-A , ANSWER: 180-54=126 - 7 years agoHelpfull: Yes(0) No(0)
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