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Numerical Ability
Trigonometry
What is the percentage error when 3 resistors with ratings 100 Ω at 5%, 150 Ω at 6% and
250 Ω at 8% respectively, are connected in series?
A) 6.33% B) 6.80%
C) 19% D) None of these
Read Solution (Total 2)
-
- total error=100*.05+150*.06+250*.08
per(%)=(total error/total value)*100=(34/500)*100=6.80%
B) - 9 years agoHelpfull: Yes(0) No(0)
- B). 6.80% REGISTER 100*5/100+150*6/100+250*8/100 = 34 NOW TOTAL IS= 100+150+250=500 % = 34/500/100=6.80%
- 8 years agoHelpfull: Yes(0) No(0)
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