SSC
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Numerical Ability
Geometry
ABC is a right angled triangle , AD is perpendicular to the hypotenuse BC if AC = 2AB ,
then the value of BD is
Read Solution (Total 4)
-
- ans is BC/5
- 9 years agoHelpfull: Yes(3) No(0)
- in trng ABD and trngl ACD
angle ADB = angle ADC
AD =AD
hence trng ABD ~ trng ACD
CD/BD=AC/AB
ADDING 1 BOTH SIDES
CD/BD +1 = AC/AB+ 1
BC/BD= AC + AB /AC
BD= BC/3 - 9 years agoHelpfull: Yes(1) No(4)
- ans. ABsqrt(5)/2
bc^2=ab^2+ac^2
=ab^2+4ab^2=5ab^2
then bc=sqrt(5)*ab
then bd=bc/2=sqrt(5)*ab/2 - 9 years agoHelpfull: Yes(0) No(3)
- Answer is not Bc/3.
Angle bad not equal to dac, but Angle bad equal to dac. - 8 years agoHelpfull: Yes(0) No(0)
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