51^103 divided by 7.the remainder is

• 2.
  51%7==2.
  and (2^3)%7 rem==1
  103%4==1
  51^103==2^103==2^1
  so remendr ==2
  
• 9 years agoHelpfull: Yes(1) No(1)
• 51^103/7...(7*7+2)^103/7..2^103/7
  2^1=2..2^2=4..2^3=8..2^4=16..2^5=32..so last digits will be repeated for every 4 powers..2,4,8,6,2,4...so remainder of 2^3/7..1
• 7 years agoHelpfull: Yes(0) No(0)