Area of a right-angled triangle is doubled while the base is reduced to its half. What % increase occurs in its height?

• 400%
  
  With height=h, base=b Area =(1/2)*b*h
  As area is doubled(=b*h), while base reducing to half and if height is increased to x times
  So (1/2)*(b/2)*(h*x)=b*h, x=4
  As height needs to be increased from h to 4*h, which is four times or 400% of original height.
• 9 years agoHelpfull: Yes(0) No(0)
• the height increases 4 times so shouldn't the % increase b 300%?
  (4h-h)/h*100
  or
  original height h1= 2A/b (as A=(1/2)*b*h)
  new A= 2A, new b = b/2
  new height h2= 8A/b
  % increase= ((8A/b)-(2A/b)) *100 / (2A/b) = 300%
  
• 9 years agoHelpfull: Yes(0) No(0)
• ans : 300%
  
  height=h, new height=H
  initially area = (1/2)*(b)*(h)
  new area = (1/2)*(b/2)*H = 2*(1/2)*b*h
  therefore H=4h
  increase % = (4h-h)/h * 100 = 300%
• 9 years agoHelpfull: Yes(0) No(0)