A 1423-kg car is moving along a level highway with a speed of 26.4 m/s. The driver takes the foot off the accelerator and the car experiences a retarding force of 901-N over a distance of 106 m. Determine the speed of the car after traveling this distance

• Retardation =√(901÷1423)=0.795m/s^2
  Final speed=√(26.4^2 - 2*0.795*106)=22.96m/s
• 7 years agoHelpfull: Yes(1) No(5)