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LCM and HCF
Colonel & General & Major started a work together for 816. Colonel & Major did 8/17 of the total work, while Major & General together did 12/17 of the whole work. What is the amount of the least efficient worker
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- Let the total work = 1 unit, then
C+M+G = 1 ........(1)
C+M = 8/17 .......(2)
M+G = 122/17 ....(3)
by solving C = 5/17 , G = 9/17 , M = 3/17
so the least efficient worker is Major
amount of Major = 3/17
time taken by him = 816*3/17 = 144 days - 9 years agoHelpfull: Yes(7) No(0)
- work done by major=8/17+12/17-1=3/17 of the work
colonel do=8/17-3/17=5/17
general do=12/17-3/17=9/17
least efficient=major
amount of least efficient=3/17*816=144 - 9 years agoHelpfull: Yes(3) No(0)
- general is the least efficient worker.
with 435 days
- 9 years agoHelpfull: Yes(1) No(3)
- Major is least sufficient worker he had done only 3/17 of total work
- 9 years agoHelpfull: Yes(0) No(1)
- Major is least efficient worker with 134 days
- 9 years agoHelpfull: Yes(0) No(2)
- Colonel, Major and General started a work together for Rs. 816. Colonel and Major did 8/17 of the total work, while Major and General together did 12/17 of the whole work. What is the amount of the least efficient person?
- 6 years agoHelpfull: Yes(0) No(0)
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