Elitmus
Exam
Numerical Ability
If x and y are integers, Then how many possible equations can be formed for
5|X| + 2|Y| = 100.
Read Solution (Total 8)
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- 4 equations are formed since mod function are defined in this way +x whenx>0 and -x when x
- 9 years agoHelpfull: Yes(6) No(0)
- Ans- 9 possible equ.
5x18 +2x5 =100
5x16 +2x10=100
5x14 +2x15 =100
5x12 +2x20=100
5x10 +2x25=100
5x8 +2x30 =100
5x6 +2x35=100
5x4 +2x40=100
5x2 +2x45 =100
- 9 years agoHelpfull: Yes(6) No(10)
- answer is 11
0+100=100
10+90=100
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100+0=100
so total 11 - 9 years agoHelpfull: Yes(3) No(2)
- @Piya.. How comes 80??
- 9 years agoHelpfull: Yes(1) No(0)
- ans - 76 solutions
(0,50)(0,-50) ------> 2 EQUATIONS
(2,45)(-2,45)(-2,-45)(2,-45),(45,2)(-45,2)(-45,-2)(45,-2) ----> 8 equations
(4,40)(-4,40)(-4,-40)(4,-40),(40,4)(-40,4)(-40,-4)(40,-4) ----> 8 equations
(6,35)(-6,35)(-6,-35)(6,-35),(35,6)(-35,6)(-35,-6)(35,-6) ----> 8 equations
(8,30)(-8,30)(-8,-30)(8,-30),(30,8)(-30,8)(-30,-8)(30,-8) ----> 8 equations
(10,25)(-10,25)(-10,-25)(10,-25),(25,10)(-25,10)(-25,-10)(25,-10) ----> 8 equations
(12,20)(-12,20)(-12,-20)(12,-20),(20,12)(-20,12)(-20,-12)(20,-12) ----> 8 equations
(14,15)(-14,15)(-14,-15)(14,-15),(15,14)(-15,14)(-15,-14)(15,-14) ----> 8 equations
(16,10)(-16,10)(-16,-10)(16,-10),(10,16)(-10,16)(-10,-16)(10,-16) ----> 8 equations
(18,5)(-18,5)(-18,-5)(18,-5),(5,18)(-5,18)(-5,-18)(5,-18) ----> 8 equations
(20,0)(-20,0) ------> 2 EQUATIONS
All together 2+8+8+8+8+8+8+8+8+8+2 = 76 - 9 years agoHelpfull: Yes(1) No(3)
- 20,0 (+ + ; - +)
18,5 (+ - ; + + ; - +; - -)
16,10 (+ - ; + + ; - +; - -)
14,15 (+ - ; + + ; - +; - -)
12,20 (+ - ; + + ; - +; - -)
10,25 (+ - ; + + ; - +; - -)
8,30 (+ - ; + + ; - +; - -)
6,35 (+ - ; + + ; - +; - -)
4,40 (+ - ; + + ; - +; - -)
2,45 (+ - ; + + ; - +; - -)
0,50 (+ - ; + +)
Total 4*9 + 2 +2 = 40 Ans : - 9 years agoHelpfull: Yes(1) No(0)
- 80 equation ...
- 9 years agoHelpfull: Yes(0) No(1)
- Ans: 4
Solution: 5x+2y=100, 5x-2y=100, 2y-5x=100, 5x+2y=-100. - 9 years agoHelpfull: Yes(0) No(0)
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