Elitmus
Exam
Numerical Ability
Number System
find the least number that when divided by 16,18 and 20 leaves the same remainder 4 in each case but it is completely divisble by 7
Read Solution (Total 10)
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- LCM of 16,18,20 is 720...
(720+4)is not divisible by 7...
(720*2+4)not divisible by7..
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(720*4+4)divisible by 7....
so the ans is... 2880+4=2884 - 9 years agoHelpfull: Yes(37) No(0)
- we found lcm of 16,20,18 is 720
for completely divisible by 7
(720*n)+4 is completely divisible by 7
so remender is (6n+4) is divisible by 7
n=4 satisfied
so answer is 720*4+4=2884 - 9 years agoHelpfull: Yes(9) No(0)
- first we have to find out the LCM of 20,18,16=720
now 2nd condition of question i.e divisibility of 7 ,
now check it ..720+4=724 ..this is not divide by 7
so check another number which is multiple of 720
.
.
so finally i got 720*4=2880
then we add 4 in this number 2880+4=2884 this divisible by 7. - 9 years agoHelpfull: Yes(1) No(3)
- lcm of the 16,18,20 is 720, and least number leaves the remainder 4 is 720+4,so while dividing 724 with 7 we get the remainder 3, 720*2+4 is while dividing give the remainder is 2, so 720*3+4 is while dividing it gives remainder 1,finally 720*4+4 is 2884 / 7 gives 0 remainder so ans is 2884
- 9 years agoHelpfull: Yes(1) No(0)
- l.c.m of 16,18 & 20 will be 720
and the 2nd condition is must be divisible by 7
so 720+4=724 is not divisible by 7
now (720*n)+4 will be divisible by 7
(720*2)+4=1444 which is not divisible by 7
(720*3)+4=2164 which is also not divisible by 7
now
(720*4)+4=2884 which is completely divisible by 7
so condition satisfied
- 9 years agoHelpfull: Yes(1) No(0)
- ans is 2884
- 9 years agoHelpfull: Yes(0) No(2)
- 144
as LCM OF 16,18 AND 20 is 140.
which also divisible by 7....so add 4 - 9 years agoHelpfull: Yes(0) No(11)
- 144
as LCM OF 16,18 AND 20 is 140.
which also divisible by 7....so add 4 - 9 years agoHelpfull: Yes(0) No(6)
- 364 is the correct answer
- 9 years agoHelpfull: Yes(0) No(2)
- take the LCM of 20,18,16= 720
now
the no will be in form of 720x+4
2nd condition of question i.e divisibility of 7 ,
So check it
let x=1..720x+4=724 but this is not divisible by 7 ,so hit and trial and when we put x=4
= 720*4=2880
Now, add 4 in the number 2880+4=2884 and this divisible by 7. - 2 years agoHelpfull: Yes(0) No(0)
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