A mixture has milk and water in the ratio 5:1. 20 liters of water is added and the ratio now becomes 5:6. How much milk was present in original mixture?

• 20 liters
  
  If milk and water in original mixture is 5x and x respectively, then
  5x/(x+20) = 5/6, x=4
  So milk in original mixture=5*4=20 liters
• 8 years agoHelpfull: Yes(33) No(0)
• ratio of milk and water is=5:1
  let x:y=5:1---------(1)
  after adding 20 liters of water the ratio becomes=5:6
  x:y+20=5:6---------(2)
  solve (1) &(2)
  and you can get the answer as x=20,y=4
  therefore milk present in original mixture,x=20 liters
  
• 8 years agoHelpfull: Yes(6) No(0)
• Let in first mixture water is x.and in second mixture water become 6x.
  So ,x+20=6x.
  X=4
  So .water is 4 lit in original mixture
• 8 years agoHelpfull: Yes(0) No(4)
• can anyone send me the ibm link to apply the job..my mail id:ulsindhu.ece@gmail.com
• 8 years agoHelpfull: Yes(0) No(0)
• given : 20 liters were added to 5:1 mixture in order to get 5:6 mixture
  so that means here 5 parts of mixture = 20 lit 0f water
  so 1 part = 5 liters
  then original milk =5*4=20 liters
• 8 years agoHelpfull: Yes(0) No(0)
• water/milk=5x/[x+20]=5/6
  30x=5[x+20]
  25x=100
  x=4
• 8 years agoHelpfull: Yes(0) No(1)
• m:w=5:1=> m=5x,w=x
  5x/(x+20) =5/6 by cross multiplication we get x=4lt
  original milk content is 5*4=20lt
• 8 years agoHelpfull: Yes(0) No(0)
• 5x/1x+20=5/6
  5x+100=30x
  x=4
  5(4)=20
• 8 years agoHelpfull: Yes(0) No(0)
• assume total liters as 'x'
  total mixture x x
  initial ratio 5:1 a:b
  water added 20 w
  new ratio 5:6 c:d
  20=x(5*6-5*1)/(5*6)
  =24 w=x(ad-bc)[c(a+b)]
  milk =(5/6)*24=20
  20 liters of milk is present
• 8 years agoHelpfull: Yes(0) No(0)
• ans 20
• 5 years agoHelpfull: Yes(0) No(0)