Find the output.
main()
int i;
pf("%d",i);

1.0
2.NULL
3.GARBAGE VALUE
4.COMPILE ERROR

• garbage value
• 8 years agoHelpfull: Yes(4) No(0)
• 3
  uninitialized values are assigned garbage values
• 8 years agoHelpfull: Yes(2) No(0)
• Garbage Value.
  
  Variables point to a location in the memory where some random value may be residing due to previous execution or due to some other program. Hence, uninitialized variables may print some garbage value.
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• printf is placed out of the scope of the main()
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• 3. garbage value
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• ans 3
  sice i is nt initialized
  
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• option 4 as pf will nt read by compiler
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• garbage value
  
  
  becoz unintialize value assigned garbage value.
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• 3 garbage value
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• 3.garbage value because it doesnt initialised
  
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• ans:3 i.e garbage value
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• compile error
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• GARBAGE VALUE
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• garbage value
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• compilation error. because we cannot write pf(). it should be printf().and also expected '}' at the end
  
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• garbage value because variable i is not initialized
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• 3. GARBAGE VALUE
  
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• garbage value
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• garbage value because in c default values are garbage values
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• ans may be zero or any value
  Accessing an unitialized variable is undefined behavior in both C and C++ so it can give any value 0 or any value.It is also possible that your program crashes:
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• option 4
  compilation error
  coz all the codes has been written outside the main as main does not contain opening braces
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• 3. GARBAGE VALUE
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• its compile error because of declaration syntax error
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• option 1
  by default integer values taken as 0
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