there is a cask full of milk E litres of milk are drawn from the cask and replaced with water

ans is 5E.
9 years agoHelpfull: Yes(1) No(0)
Ans: 2)5E
9 years agoHelpfull: Yes(1) No(0)
The ratio is given as 16:9.
let x be the initial qty and assume that the process done in 2 times.
after one replacement proportional of milk left x-e/x,after two (x-e/x)^2,
the ratio is given as 16:9 i.e, milk to water ratio,milk would be 16/9.
(x-e/x)^2=16/9
x-e/x=4/3 [take x=1]
=> 1-(e/x)=4/3
1-4/3=e/x
-1/3=e/x
x=-3E.
for 2 times of this process repetition the answer is '-3E'. similarly, for 3 or more times of repetition of this process, the answer should be decimal multiples of E (example: 2.1467E).
So the answer should be in negative or in decimal points only. So, there is no option like that (Because 'E' multiplied by negative value or fraction only).
So, definitely, the answer should be "cannot be determined".
9 years agoHelpfull: Yes(0) No(3)
its 100% cannot be determined because 5E represents 5 timess of E quantity which is impossible and 3E represents the same E+9 is also impossible because already cask is full so E+9 is also impossible so the answer is D
8 years agoHelpfull: Yes(0) No(0)
my Answer is 4 coz we replace the e litres from cask nd we dont know what is E nd what is the capacity of E
8 years agoHelpfull: Yes(0) No(0)
((x-e)/x)^2 = 16/25
(x-e)/x = 4/5
1-(e/x) = 4/5
1-(4/5) = e/x
1/5 = e/x
x = 5e
8 years agoHelpfull: Yes(0) No(0)

there is a cask full of milk. E litres of milk are drawn from the cask and replaced with water. this process is repeated. now ratio of milk and water is 16:9. what is the capacity of the cask in litres?
1. E+9
2. 5E
3. 9E
4. cannot be determined