log(b(b(b........)^1/2)^1/2)^1/2 ?
base=b
Options-0,1/2,1/3,1

• sorry right answer is 1.
  
  1/2(1+1/2+1/2^2+----------------)=1/2*(1/1-1/2)=(1/2)*2=1 infinite sum of GP is a/1-r
• 9 years agoHelpfull: Yes(21) No(1)
• ans . 1 is correct
• 9 years agoHelpfull: Yes(3) No(2)
• let (b(b(b........)^1/2)^1/2)^1/2) =x
  therefore log(bx)^1/2 = (1/2)logb +(1/2)logx
  since base =b
  so, 1/2 + 1/4 + 1/8 +............ = 1
• 9 years agoHelpfull: Yes(3) No(1)
• the form become 1/2 1/4 1/8 1/16....
  so nth term=a/1-r...
  1/2/(1-1/2)
• 9 years agoHelpfull: Yes(2) No(0)
• 1/2.
  
  Using logb=log a+logb
  
• 9 years agoHelpfull: Yes(1) No(6)
• 1/2 is correct answer (1/2+1/2^2+1/2^3+.................)
  1/2(1+1/2+1/2^2+...........)=1/2*(1)=1/2
• 9 years agoHelpfull: Yes(1) No(3)
• 1
  As we know log 10 whose base also 10 is 1 so log b whose base also b will be 1.
• 9 years agoHelpfull: Yes(0) No(0)