If 4^a=5 5^b=6 6^c=7 7^d=8 Then find the value of abcd

• Given :-4^a=5, 5^b=6, 6^c=7 , 7^d=8
  Now taking log on both sides , we get
  alog4=log5 》》》 a=log5/log4
  blog5=log6 》》》 b=log6/log5
  clog6=log7 》》》 c=log7/log6
  dlog7=log8 》》》 d=log8/log7
  Therefore ,abcd = log8 /log4 》》》 3log2/2log2 》》 3/2
  abcd=3/2
  
• 8 years agoHelpfull: Yes(2) No(1)
• 4^a=5 --> a=log5 4 --> a=log4/log5
  similarly b=log 6/log5, c=log7/log6, d=log8/log7
  now abcd= log8/log 4 --> log4 8
• 8 years agoHelpfull: Yes(0) No(1)