Crypt Problem in today's eLitmus exam 19/07/2015
WAV
MMS
-----------
GSVG
SXAX
SXAX
-------------
WKSASG
-------------

• 457
  883
  ------------
  1371
  3656
  3656
  -------------
  403531
  
  note--- see s and w is two consecutive no. and product of them is 4 digit so try 3,4 and more
  and try 1 for G and solve.
  
• 9 years agoHelpfull: Yes(9) No(1)
• 4 5 7
  8 8 3
  1 3 7 1
  3 6 5 6 *
  3 6 5 6 * *
  4 0 3 5 3 1
  
• 9 years agoHelpfull: Yes(8) No(1)
• I tried a lot in exam but i was unable to solve it
• 9 years agoHelpfull: Yes(6) No(0)
• Hints:-
  1. w=s+1
  2. s+x=9 or 10
  3. v+x= _s
  4. now start hit and trail for value of 'W' ans 'S' you will get solution within 10 min max.... :)
• 9 years agoHelpfull: Yes(4) No(2)
• can any one plz plz plz provide me material for cryptoarrithmatic every question has different solutions and it is making me very nervous about my preparationa , my email id is-akhilkalra052@gmail.com
• 9 years agoHelpfull: Yes(4) No(0)
• STEP-1
  fIND DIGIT WHICH CAN NOT 0-(W,M,S,G,V)
  DIGIT WHICH CAN NOT 1-(M,S,W,V)
  STEP-2:
  W=S+1(I.E W>2 BCZ S NOT EQUAL T0 1)
  STEP -3:
  BY HEAT AND TRIAL METHOD PUT THE VALUE OF W AND S
  1)LET W=3,S=2(V+X=S) SO POSSIBLE VALUE OF V,X(5,7),(4,8)(3,9)
  NOW TACKING THE VALUE OF V=5,X=7,W=3,S=2
  THEN G=0(V*S) WHICH IS NOT POSSIBLE
  2)LET W=3,S=2,V=4,X=8
  THEN G=8 NOT POSSIBLE BCZ IN THIS CASE X=8 ALREADY
  3)LET W=3,S=2,V=3,X=9
  THEN G=6 BUT(THIS IS NOT POSSIBLE BCZ (S+A+X+C2=A BUT IN THIS CASE S+X=11)
  SIMILARLY CHECK IT SATISFIES WHEN
  W=4,S=3,V=7,X=6,A=5,K=0,M=8,G=1
  457
  883
  -----
  1371
  3656
  3656
  -----
  403531
• 9 years agoHelpfull: Yes(4) No(1)
• W A V
  M M S
  -----------
  G S V G
  S X A X
  S X A X
  -------------
  W K S A S G
  -------------
  
  
  This approach may be lengty sometimes but i Got the answer in my first attempt.
  
  just break the Equation as such
  
  W A V
  * S
  -----------
  G S V G
  
  
  Now start putting the value of G start from 1 because in the given equation we have many similar terms like G(2 times), V(2 times), S (2 times). So it reduceses our calcualtions.
  
  
  So we start here by puting G=1
  
  we Know to get G=1 , we only have 7(V)*3(S) =21... so G=1 and 2 will be carry (To make G=1 we cannot take 9*9 because as we kw two alpha cannot have the same value ok )
  
  so put V=7 and S=3 in the whole Equation
  
  
  W A 7
  * 3
  -----------
  1 3 7 1
  
  So to make S=3 and V=3 in whole Equation we have to put W=4 and A=5
  
  and after that its a cakewalk.
  
  
  
• 9 years agoHelpfull: Yes(4) No(0)
• 4 5 7
  8 8 3
  ----------------
  1 3 7 1
  3 6 5 6 -
  3 6 5 6 - -
  ------------------------------
  4 0 3 5 3 1
  
  1=>S+1=w
  2=>S+X+Carry=K+1 Try from 1-3, 3 will best suited here for S and 6 for X
  Also V+X=S so V,X=(7,6) 7+6=13=S+1 Carry.
  And accordingly you can solve it completely.
  I tried it in exam 3 times and I got the ans in 3rd try, felt relaxed.
• 9 years agoHelpfull: Yes(2) No(1)
• To start solving Cryptarithm problem what I understand, is to find the relation like A*B=A which gives two possibilities as follows :
  1) A is 5 and B is odd no.
  2) A is even no. and B is 6
  
  But in this particular problem there is no such relation so how should we begin. Please explain
• 9 years agoHelpfull: Yes(1) No(0)
• Seriously.. it was pretty much tough on that moment. I spend 10 mins then I gave up in that question
• 9 years agoHelpfull: Yes(1) No(0)
• 457
  *883
  ------------
  1371
  3656*
  3656**
  ----------
  403531
  ----------
• 9 years agoHelpfull: Yes(1) No(0)
• 1371
  3656*
  3656**
  40351
• 9 years agoHelpfull: Yes(1) No(0)
• Putting X=1,2,3,4,5,6
  you will get M=8,and V=7 FOR X =6
  Solve it S=3
• 9 years agoHelpfull: Yes(0) No(1)
• if any one remember today's exam 3 questions based on this please post
• 9 years agoHelpfull: Yes(0) No(0)
• I am agree with @chandan solution......
• 9 years agoHelpfull: Yes(0) No(1)
• its 457*883
  w=4
  s=5
  v=7
  M=8
  S=3
  G=1
  X=6
  A=5
  K=0
• 9 years agoHelpfull: Yes(0) No(0)
• can any one plz plz plz provide me material for cryptoarrithmatic every question has different solutions and it is making me very nervous about my preparationa , my email id is shrutisingh14nov@gmail.com
  
• 9 years agoHelpfull: Yes(0) No(0)
• Here logic is s+carry=w,carry may be 1or 2
  AV*S=VG from the first line so let us try the value of S-2,3,4
  457
  883
  -----------
  1371
  3656*
  3656*
  ---------
  403531
• 9 years agoHelpfull: Yes(0) No(0)
• here hint is mms which means m could be 2,3,4....9so do hit and trial taking one value of at a time and proceed ans is
  457
  883
  ------------
  1371
  3656
  3656
  ----------
  403531 ans
  hit and trial
• 9 years agoHelpfull: Yes(0) No(0)
• Hii friend any body can tell me the solving logic ,,,my cont no is-8585086122
• 9 years agoHelpfull: Yes(0) No(0)
• 475
  883
  _____
  1371
  3656
  3656
  _______
  403531
• 9 years agoHelpfull: Yes(0) No(0)
• 457
  883
  ------------
  1371
  3656
  3656
  ----------
  403531
  ------------
• 9 years agoHelpfull: Yes(0) No(0)