Set x1 to 1;
Set x2 to 1;
While(x1 < 10)
Set x2 = x2 + x1 + 1;
Set x1 = x1 + 1;
write x2
(a) Arithmetic progression
(b) Tribonacci series
(c) Fibonacci series
(d) Triangular numbers

• Write x2 will print the following numbers one by one,
  1 3 6 10 15 21 28 36 45 55, here the operation ceases since x1 reaches the value 10.
  The above series of numbers form the Triangular series 0 1 3 6 10 15 21 28 36 45 55 66 78 91 ...
  Thus the correct option is D.
• 9 years agoHelpfull: Yes(7) No(0)
• traingular
  
• 9 years agoHelpfull: Yes(2) No(1)
• option d-Triangular numbers
  https://en.wikipedia.org/wiki/Triangular_number
• 9 years agoHelpfull: Yes(1) No(0)
• TRIANGULAR NUMBERS
  OPTION D IS THE CORRECT ANSWER
• 9 years agoHelpfull: Yes(1) No(0)
• d is the correct ans
• 9 years agoHelpfull: Yes(1) No(0)
• option a-arithmetic progression
• 9 years agoHelpfull: Yes(0) No(9)
• x2=
  1
  3
  6
  10.......so ,they are triangular numbers
• 9 years agoHelpfull: Yes(0) No(0)
• since x+1 is incrementing its values by 1 each time and the values of the x2 is incrementing with 1 3 6 so it follows triangular series
  
• 9 years agoHelpfull: Yes(0) No(0)
• But it does not print 1 as x2 set is 3 when 1
• 8 years agoHelpfull: Yes(0) No(2)
• the series for x2 is 1,3,6 which is a triangular number series.so option d is correct.
• 7 years agoHelpfull: Yes(0) No(0)
• (a) as sequenvce is 3 6 10 15
• 7 years agoHelpfull: Yes(0) No(0)
• arithmetic progression
• 6 years agoHelpfull: Yes(0) No(2)
• Fibonaccci series c
• 6 years agoHelpfull: Yes(0) No(0)
• airthmetic progression
• 6 years agoHelpfull: Yes(0) No(0)