The sum of the three numbers is 98. if the ratio between the first & second is 2:3 & that between the second and third is 5:8 , then the second number is ??

• a:b =2:3 and b:c =5:8
  => b:c = (5*3/5) : (8*3/5) (multiplying with 3/5 on both sides to make b ratio 3)
  => b:c = 3 : (24/5)
  => a:b:c = 2:3:(245)
  => a:b:c = 10:15:24
  a+b+c = 10x+15x+24x =98
  =>49x=98
  =>x=2
  so second number is 30
• 9 years agoHelpfull: Yes(1) No(0)
• a+b+c=98
  a/b=2/3 >>a=2b/3
  b/c=5/8 >>c=8b/5
  so putting these values in eqn 1
  2b/3+b+8b/5=98
  b=36.ans
• 9 years agoHelpfull: Yes(0) No(2)
• Total Sum of three Numbers is 98.Assume them to be a,b,c
  
  a:b=2:3
  
  b:c=5:8
  
  
  a+b+c=98
  
  
  Given
  a:b=2:3
  
  so,
  a/b=2/3
  a=2b/3
  
  Given
  b:c=5:8
  b/c=5/8
  
  c=8b/5
  
  
  Now Substituting in the equation a+b+c=98
  (2b/3)+b+(8b/5)=98
  10b+15b+24b=1470
  
  b=30
  
  Then
  a=20======>a=2b/3=(2*30)/3
  
  c=(8*30)/5=48
• 9 years agoHelpfull: Yes(0) No(0)
• A;B=2:3 AND B:C=5:8 then A:B:C=10:15:24 after that we have to find 10x+15x+24x=98(given), we obtain x=2 den second number is 15*2=30 ans
• 9 years agoHelpfull: Yes(0) No(0)
• x:y=2/3.
  y/z=5/8
  so ,x:y:z=10:15:24
  y=30
  
• 9 years agoHelpfull: Yes(0) No(0)