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a hollow cube of size 5 cm is taken,thickness=1 cm. it is made into smaller cubes of size 1 cm, if 1 face of the outer surface of the cube is painted, how many faces of the smaller cubes remain unpainted?
Read Solution (Total 16)
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- total no of smaller cubes= 25+25+15+15+9+9=98
painted face of bigger cube=1=25 small faces
total faces of smaller cube=98*6=588
remaining unpainted faces=588-25=563 - 9 years agoHelpfull: Yes(6) No(0)
- vol of big cube= 5^3-3^3=98
so no of small cube =98
so no of faces in smallcube =98*6=588
1 face of big cube is painted means 25 faces painted in small cube
so unpainted face in small cube is =588-25= 563 - 9 years agoHelpfull: Yes(4) No(0)
- total no of smaller cubes= 25+25+15+15+9+9=98
no. of phases of bigger cube painted=1 = 25 small cubes
therefore total no of unpainted cubes=98-25=73 - 9 years agoHelpfull: Yes(1) No(0)
- Number of smaller cubes=25*2+15*2+9*2=98
Number of faces of smaller cubes=98
Number of faces of smaller cubes painted=25
Number of unpainted faces=98-25=73 - 9 years agoHelpfull: Yes(0) No(0)
- volume of bigger cube 5*5*5= 125
so there is 125 smaller cubes
1 face is painted of bigger cube
so unpainted smaller cubes 125-25=100 - 9 years agoHelpfull: Yes(0) No(0)
- how is it i mean 25 15 and 9???
- 9 years agoHelpfull: Yes(0) No(0)
- one side of biger cubes has 25 faces of smaller cube
bcoz 5*5
and totle 588faces (98*6)
(125-27=98)
total no of sml cube is 98cm3/1cm3=98
so 588-25=ans - 9 years agoHelpfull: Yes(0) No(0)
- can anyone explain the answer a little more vividly! 25*2+15*2+9*2 ??
- 9 years agoHelpfull: Yes(0) No(0)
- please explain this question............
- 9 years agoHelpfull: Yes(0) No(0)
- 563 is the right answer.....
- 9 years agoHelpfull: Yes(0) No(0)
- 3*3*3-2*2*2=98
98*6=588
588-4*25=
488 - 9 years agoHelpfull: Yes(0) No(0)
- Total no of cubes is 125 but this is hallow cube so total no of cube is 125-27=98 . 1 cube have 6 face . So total no of faces 98*6=588. Now 1 side is painted so 25 faces are already painted so total no unpainted faces are 588-25=563 is the ans.
- 9 years agoHelpfull: Yes(0) No(0)
- length of each side = 5cm + 2*1 cm=7cm
to make each cube of length of 1 cm we have to cut that cube into 7 smaller cubes
the unpainted smaller cubes= (7-2)^3 =125 [ .". (n-2)^3 ] - 9 years agoHelpfull: Yes(0) No(0)
- 588-100=488
- 9 years agoHelpfull: Yes(0) No(1)
- corner cubes have 3 faces painted and 3 unpainted and 8 corners are there .so 8*3=24 faces
12 edges are there on which each is having 3 cubes whose 2 faces are painted and 4 are unpainted=4*12*3=144.
9 cubes are remaining on each face of big cube.so 1 painted and 5 unpainted in those faces=9*6*5=270
so total no. of unpainted faces are= 24+270+144=438 - 9 years agoHelpfull: Yes(0) No(0)
- The Hallow cube volume = n3−(n−2)2, Here n is the number of small cubes lie on the big cube edge.
Now n = 5 so Hallow cube volume = 53−(5−2)2=125−27=98
So 98 small cubes required to make a hallow cube of size 5 cm. Now total surfaces = 6 x 98 = 588
Now if the bigger cube is painted 1 side, total 1 x 25 small faces got paint. So remaining small faces which does not have paint after cutting is 588 - 25 = 563 - 9 years agoHelpfull: Yes(0) No(0)
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