A and B are two alloys of argentums and brass prepared by mixing metals in proportions 7:2 and 7:11 respectively. if equal quantities of the two alloys are melted to form a third alloys C , the proportion of argentums and brass in C will be ??

• 7:5
  
  In A, argentums and brass in A is 7/9 and 2/9 respectively in B it is 7/18 and 11/18 respectively
  When mixing A and B in equal quantities ratio of argentums and brass = (7/9)+(7/18) / (2/9)+(11/18)
  =(21/18) : (15/18)
  =7:5
• 9 years agoHelpfull: Yes(4) No(0)