Certain positive integers have these properties: (I).the sum of the squares of their digits is 50 (II) each digit is larger than one to its left. The product of the digits of the largest integer with both properties is

• Integers that exhibit the given properties are 17,1236,345
  the largest integer among those is 1236
  so product of the digits of 1236 is 36.
  hence ans is 36.
• 9 years agoHelpfull: Yes(4) No(3)
• ans is 60 ... + int is 345 n 3^2+4^2+5^2=50 so product is 3*4*5=60
  
  
• 9 years agoHelpfull: Yes(1) No(0)
• We see that, 3^2+4^2+5^2=50
  & 4 is 1 more than 3.
  & 5 is 1more than 4.
  so that, 2 conditions are satisfied.
  then, our answer will be,
  3*4*5=60.
• 9 years agoHelpfull: Yes(1) No(0)
• 3^2+4^2+5^2=50. So number is 345. and product of its digits is 5*4*3=60
• 9 years agoHelpfull: Yes(0) No(0)
• take three digit number and satifying the two conditions i can make the interger having the digits like
  (x-1)(x)(x+1) this satisfies the second condition and
  (x-1)^2+x^2+(x+1)^2=50
  =>x^2-2x+1+x^2+x^2+2x+1=50
  =>3x^2+2=50
  =>x^2=16
  x=4,-4
  so x=4
  and integer is 345=>3^2+4^2+5^2=50
  and some one also answer as 17,1236,345 .of these the number that satisfies the conditions is only 345. so 345 is the answer
• 5 years agoHelpfull: Yes(0) No(0)