-Adrian and Betty have been teaching for a total of 36 years.

-Charlie and Betty have been teaching for a total of 22 years.

-Charlie and Adrian have been teaching for a total of 28 years.

How long has each been teaching?


OPTIONS
1)20
2)21
3)22
4)23
4)24
5)25
6)26
7)27
8)28
9)29
10)None

• adrian and betty together teaches for 36 yrs...(adrian+betty=36)--------eq 1
  betty and charlie together teaches for 22 yrs...(betty+charlie=22)-------eq2
  charlie and adrian together teaches for 28 yrs...(charlie+adrian=28)-----eq3
  now addind equation 1,2,3...we get....
  2(adrian+beety+charlie)=86
  now,(adrian+betty+charlie)=43--------eq 4
  again,subtracting eq 1,2 and 3 respectively from eq 4....we get charlie=7,adrian=21 and betty=15
• 9 years agoHelpfull: Yes(1) No(0)
• adrian and betty together teaches for 36 yrs...(adrian+betty=36)--------eq 1
  betty and charlie together teaches for 22 yrs...(betty+charlie=22)-------eq2
  charlie and adrian together teaches for 28 yrs...(charlie+adrian=28)-----eq3
  now addind equation 1,2,3...we get....
  2(adrian+beety+charlie)=86
  now,(adrian+betty+charlie)=43--------eq 4
  again,subtracting eq 1,2 and 3 respectively from eq 4....we get charlie=7,adrian=21 and betty=15
  Read more at http://www.m4maths.com/frequently-asked-placement-questions.php?SOURCE=Bank%20Exam#UxFUUZahhQbmjtRc.99
• 9 years agoHelpfull: Yes(1) No(0)
• Adrian=A
  Betty=B
  Charlie= C
  
  A+B=36
  C+B=22
  A+C=28
  C=22-B
  SOLVING THESE 3 equations with substitution we get A=21 B=12
  C=4... only 21 z present!
• 9 years agoHelpfull: Yes(0) No(1)
• Adrain=21,Betty=15,Charlie=7..
• 9 years agoHelpfull: Yes(0) No(0)