D and E are the midpoints of AB and AC of triangle ABC; BC is produced to any point P;DE , DP & EP are joined, then
1. trng PED=1/4TRNG ABC
2.TRNG PED =TRNG BEC
3. TRNG ADE =TRNG BEC
4. TRNG BDE = TRNG BEC

• In triangle ABC, D is mid point of AB and E is mid point of AC (Given)
  AD / AB = AE / AC = 1/2 ................................................................... (i)
  so Triangle ADE is similar to Triangle ABC
  thus => area of tri (ADE) / area of tri (ABC) = AD2 / AB2 = 1/4 (from (i)).............................. (ii)
  
  Now you have to do some construction
  Draw perpendicular from E to BC and name the intersection point as F
  Similarly Draw perpendicular from E until point A and name that point as G
  Now Triangle AGE is similar to Triangle EFC (as 2 angles are equal)
  so AE/EC = EG/EF = 1
  EG = EF ...................................................... (iii)
  area (tri DEP) = 1/2 * DE * EF
  area (tri ADE) = 1/2 *DE * GE
  From eq (iii)
  area (tri DEP) = area (tri ADE) .......................... (iv)
  thus using eq (ii)
  area (tri DEP) = 1/4 area(tri ABC)
• 9 years agoHelpfull: Yes(13) No(4)
• Ans 1 draw the pic u ll get
• 9 years agoHelpfull: Yes(0) No(0)
• Ans: 1
  after drawing the picture, we get the 5 eqiualteral triangle
• 9 years agoHelpfull: Yes(0) No(1)
• can sme please explain the answer properly ?
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• plz explain it..
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• if u will take triangle as an equilateral triangle and p as a mid point of bc .then it will become easy to solve .ans is 1.
  
• 9 years agoHelpfull: Yes(0) No(0)
• option (1) trng PED=1/4 trng ABC
• 9 years agoHelpfull: Yes(0) No(0)