A student has got marks in five subjects in the ratio 2:3:4:5:6 .The maximum marks of subjects in same sequence are in ratio 6:5:8:4:7.Total percentage of marks scored by him is 48%.FInd the maximum percentage obtained by him in a subject..options: a.65 b.78 c.96 d.90

• lets marks obtain 2x,3x,4x,5x,6x.
  total marks 6y,5y,8y,4y,7y.
  addition of marks obtain=(2x+3x+4x+5x+6x)=20x
  addition of total marks=(6y+5y+8y+4y+7y)=30y
  so percentage=(20x/30y)*100
  (20x/30y)*100=48
  so,x/y=18/25
  as we observed 5x/4y is the maximum marks
  so 5x/4y=5/4*18/25*100=90%
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
• 9 years agoHelpfull: Yes(10) No(1)
• answer:90
  let be take the marks are 2y,3y,4y,5y,6y
  and maximum marks are 6x ,5x ,8x ,4x ,7x
  total mark he scored is 20y &and total maximum mark is 30x
  so (20y/30x)*100=48,equating this we get 100y=72x
  so putting this value in each case we get % of mark scored in each exam is (2y/6x)*100=24%
  this way we get 24%,53%,36%,90%,60%
  so answer become 90%
  
• 9 years agoHelpfull: Yes(9) No(1)