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Exam
Numerical Ability
Profit and Loss
4 DICE ARE THROWN AND THE SUM OF THE NUMBERS NOTED IS 10. FIND THE PROBABILITY THAT ALL THE NUMBERS LIE BETWEEN 2 AND 5 (both inclusive)?
Read Solution (Total 1)
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- 10/79
Sum of numbers noted on 4 dice(with six faces) to be 10 will include combinations:
( 1,1,2,6)(1,1,3,5)(1,1,4,4)(1,1,5,3)(1,1,6,2)(1,2,1,6)(1,2,2,5)(1,2,3,4)(1,2,4,3)(1,2,5,2)(1,2,6,1)(1,3,1,5)(1,3,2,4)(1,3,3,3)(1,3,4,2)(1,3,5,1)(1,4,1,4)(1,4,2,3)(1,4,3,2)(1,4,4,1)(1,5,1,3)(1,5,2,2)(1,5,3,1)(1,6,1,2)(1,6,2,1)
(2,1,1,6)(2,1,2,5)(2,1,3,4)(2,1,4,3)(2,1,5,2)(2,1,6,1)(2,2,1,5)(2,2,2,4)(2,2,3,3)(2,2,4,2)(2,2,5,1)(2,3,1,4)(2,3,2,3)(2,3,3,2)(2,3,4,1)(2,4,1,3)(2,4,2,2)(2,4,3,1)(2,5,1,2)(2,5,2,1)(2,6,1,1)
(3,1,1,5)(3,1,2,4)(3,1,3,3)(3,1,4,2)(3,1,5,1)(3,2,1,4)(3,2,2,3)(3,2,3,2)(3,2,4,1)(3,3,1,3)(3,3,2,2)(3,3,3,1)(3,4,1,2)(3,4,2,1)(3,5,1,1)
(4,1,1,4)(4,1,2,3)(4,1,3,2)(4,1,4,1)(4,2,1,3)(4,2,2,2)(4,2,3,1)(4,3,1,2)(4,3,2,1)(4,4,1,1)
(5,1,1,3)(5,1,2,2)(5,1,3,1)(5,2,1,2)(5,2,2,1)(5,3,1,1)
(6,1,1,2)(6,1,2,1) ------- Total 79
Combinations with all the numbers lie between 2 and 5 are (2,2,2,4)(2,2,3,3)(2,2,4,2)(2,3,2,3)(2,3,3,2)(2,4,2,2)(3,2,2,3)(3,2,3,2)(3,3,2,2)(4,2,2,2) ------Total 10
So probability=10/79 - 8 years agoHelpfull: Yes(0) No(0)
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