ln(e(e(e......)1/3)1/3)1/3
here 1/3 is power of each bracket
1. 0
2. 1/2
3. 1
4. not remember

• 1/3/1-1/3===>1/2
  
• 9 years agoHelpfull: Yes(2) No(0)
• it's simple man it is gp
  like 1/3+1/9+1/27...........................................................infinite
  so now
  (1/3)/(1-1/3)=1/2
  
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• (1/3)/(1-1/3)====1/2
• 9 years agoHelpfull: Yes(0) No(1)
• 4th option was 1/3.
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• Ans: 2) 1/2
  Sol: Let y =(e(e(e.........)^1/3)^1/3)^1/3
  y^3=e(e(e......)^1/3)^1/3
  y^3=e(e(e........)^1/3)^1/3
  y^3=e(y)
  y(y^2-e)=0
  y=0,sqroot(e),-sqroot(e) (we chose only positive value i,e sqroot(e))
  y=sqroot(e)
  hence ln(e)^1/2
  2*lne=2*1=2
• 9 years agoHelpfull: Yes(0) No(0)