In how many ways 11women and 5 men can be suffeled to get 11 members with atleast 3men?

• answer is 3762
  atleast 3 men means we need to incude 3 or more men for every group of 11 members.
  5c3*11c8+5c4*11c7+5c5*11c6
• 8 years agoHelpfull: Yes(7) No(0)
• 5c3*11c8+5c4*11c7+5c5*11c6
  
• 8 years agoHelpfull: Yes(2) No(0)
• 5c3*11c8+5c4*11c7+5c5*11C6=3762 ways
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• sorry... that should be 10 * 165 = 1650
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• 16C11 -( 5C0 X 11C11) - (5C1 X 11C10) - ( 5C2 X 11C9) = ANS
  first choose all possible combinations (ie. 11 people out of 11+5 people) then subtracting unfavorable cases (ie in which 0men&11 women were selected or 1 men&10 women were selected or 2 men and 9 women were selected)
  
  On solving answer comes to be 3762
  
  
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• 8 women+3 men=11 member. (out of 11 women and 5 men)
  7 women +4 men =11 member. (out of 11 women and 5 men)
  6 women+5 men=11 member. (out of 11 women and 5 men)
  so,(11c8*5c3)+(11c7*5c4)+(11c6*5c5)=3762
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• 5c3 + 11c8 = 10 + 165
  
  175
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• total no of ways=5c3*11c8+5c4*11c7+5c5*11c6=3762
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• that will be 5c3 * 11c8 + 5c4 * 11c7 + 5c5 * 11c6
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• 16c5- (11c11+(11c10*5c1)+(11c4*5c2))
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• plz explain clearly
  
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• we need 11 members with ATLEAST 3 men so..
  (11c11+5c0)+(11c10+5c1)+(11c9+5c2)+(11c8+5c3)=(1+1)+(11+5)+(55+10)+(11*15+10)=258...i think
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• answer is 3762
  atleast 3 men means we need to incude 3 or more men for every group of 11 members.
  5c3*11c8+5c4*11c7+5c5*11c6
• 8 years agoHelpfull: Yes(0) No(0)
• we need 11 members with ATLEAST 3 men so..
  (11c11*5c0)+(11c10*5c1)+(11c9*5c2)+(11c8*5c3)=(1*1)+(11*5)+(55*10)+(11*15*10)=2266...i think
  
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• 11c11+ 11c10*5c1 + 11c9*5c2 + 11c8*5c3
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• we can select atleast 3 men fromb5 men so 5c3
  and we want 11 members so remaining are 8 we take from women as 11c8
  then finally 11c8*5c3=19800
  
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• in group there has to be 3 men -for this we can select 3 men from 5 in 5c3 ways and remaining 8 from 11 women in 11c3 ways
  
  therefore total ways:- 5c3*11c3
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• 5C3 x 11C8 + 5C4 x 11C7 + 5C5 x 11C6
  = 3762
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• 11c8*5c3 + 11c7*5c4 + 11c6=3762
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• 11 women 5 men ways of selection
  8 3 11C8 * 5C3
  7 4 11C7 * 5*4
  6 5 11C6 * 5C5
  
  Hence no. of selecting is
  
  (11C8 * 5C3)+(11C7 * 5C4)+(11C6 * 5C5) =3762 WAYS
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• 5c3 * 11c8=1650
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• 16c11- (11c11 + 11c10*5c1 + 11c9*5c2)
  
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• 5c3*11c8+5c4*11c7+5c5*11c6
  =3762
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• 2442 is theans
  
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• 5c3*11c8+5c4*11c7+5c5*11c6
  
• 8 years agoHelpfull: Yes(0) No(0)
• 5c3*11c8+5c4*11c7+5c5*11c6=3762
• 8 years agoHelpfull: Yes(0) No(0)