how many zeros will be there at the end of the expression [((2!)^2!)+((4!)^4!)+((8!)^8!)+((9!)^9!)+((10!)^10!)+((11!)^11!) ?

• There will be no zero at the end of the expression because adding (2!)^2! (=4)to the remaining expression will give 4 at the ones place.
• 9 years agoHelpfull: Yes(3) No(0)
• from the given problem we get, 2! * 4! * 8! * 9! * 10! * 11!
  2! to 4! will have no zeros.
  8/5=1
  9/5=1
  10/5=2
  11/5=2
  So total of 8 zeros.
• 9 years agoHelpfull: Yes(0) No(0)
• 2!^2!------>4 as unit digit
  4!^4!------->1 as unit digit
  all others will have 0 as unit digit
  so combining them 4+1+0+0+.....wil give 5 as unit digit
  hence the answer is zero number of zeroes
• 8 years agoHelpfull: Yes(0) No(0)