select a number between 1 to 99999999. write a program in java so that you can receive a number and calculate its frequency in that given number.
(Eg: 2 in 12521222 ans: 5)

• import java.util.*;
  class test12
  {
  public static void main(String args[])
  {
  Scanner sc=new Scanner(System.in);
  int number,k,count=0,result=0;
  System.out.println("Enter no between 1 to 99999999999");
  number=sc.nextInt();
  System.out.println("Enter no to be checked");
  k=sc.nextInt();
  while(number>0)
  {
  result=number%10;
  number=number/10;
  if(result==k)
  count++;
  }
  System.out.println(count);
  }
  }
• 5 years agoHelpfull: Yes(3) No(0)
• #include
  main(){
  int i,j,k,n,c=0;
  printf("Enter any number blw 1 and 99999999n");
  scanf("%d",&n);
  printf("Enter the number to find the frequencyn");
  scanf("%d",&k);
  for(i=0;i
• 8 years agoHelpfull: Yes(1) No(5)
• import java.util.Scanner;
  
  public class NumberFrequency
  {
  public static void main(String[] args)
  {
  Scanner ac = new Scanner(System.in);
  System.out.println("Enter No. 1 to 99999999 :- ");
  long value = ac.nextLong();
  long number = value;
  
  System.out.println("Enter No. ye want check Frequency:- ");
  int no = ac.nextInt();
  int check = 0;
  int digit = 0;
  
  
  for (int i=0; i8)
  {
  System.err.println("Exceed Digit Limit......");
  System.exit(0);
  }
  int[] range = new int[digit];
  number = value;
  
  for (int i=(digit-1); i>=0 ; i--)
  {
  range[i] = (int) (number%10) ;
  number = number/10 ;
  }
  
  for (int j=0; j
• 6 years agoHelpfull: Yes(0) No(0)