The ratio of the present age of the three children is 4:7:5 and10 years ago ,the sum of their ages is 66 .Find their current ages?

• 24 ,42 ,30 years
  
  If present ages are 4x, 7x & 5x respectively, then
  Sum of ages 10 years ago=(4x-10)+(7x-10)+(5x-10)=66 ,x=6
  So their present ages are 4*6=24 , 7*6=42 & 5*6=30 years.
• 8 years agoHelpfull: Yes(2) No(0)