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A robot is programmed to move forward F meters and backwards again, say B meters, in a straight line. The Robot covers 1 meter in T units of time. On Robot's path there is a ditch at a distance FD from initial position in forward direction as well as a ditch at a distance BD from initial position in backward direction. This forward and backward movement is performed repeatedly by the Robot.
Your task is to calculate amount of time taken, before the Robot falls in either ditch, if at all it falls in a ditch.
Input Format:
First line contains total number of test cases, denoted by N
Next N lines, contain a tuple containing 5 values delimited by space
F B T FD BD, where
F denotes forward displacement in meters
B denotes backward displacement in meters
T denotes time taken to cover 1 meter
FD denotes distance from Robot's starting position and the ditch in forward direction
BD denotes distance from Robot's starting position and the ditch in backward direction
Output Format:
For each test case print time taken by the Robot to fall in the ditch and also state which ditch he falls into. Print F for forward and B for backward. Both the outputs must be delimited by whitespace
OR
Print No Ditch if the Robot does not fall in either ditch
Constraints:
First move will always be in forward direction
1 <= N <= 100
forward displacement > 0
backward displacement > 0
time > 0
distance of ditch in forward direction (FD) > 0
distance of ditch in backward direction (BD) > 0
All input values must be positive integers only
Sample Input and Output
SNo. Input Output
1
3
9 4 3 13 10
9 7 1 11 13
4 4 3 8 12
63 F
25 F
No Ditch
2
5
8 4 7 11 22
4 5 4 25 6
4 9 3 6 29
7 10 6 24 12
10 10 1 9 7
133 F
216 B
231 B
408 B
9 F
Read Solution (Total 4)
-
- give the answer for this question
- 9 years agoHelpfull: Yes(3) No(3)
- #include
#include
using namespace std;
int main(){
int f[100],b[100],t[100],fd[100],bd[100],n,time;
cin>>n;
for(int i=0;i>f[i]>>b[i]>>t[i]>>fd[i]>>bd[i];
//fwd back time fwd_ditch back_ditch
}
for(int i=0;i - 3 years agoHelpfull: Yes(1) No(1)
- A robot is programmed to move forward F meters and backwards again, say B meters, in a straight line. The Robot covers 1 meter in T units of time. On Robot's path there is a ditch at a distance FD from initial position in forward direction as well as a ditch at a distance BD from initial position in backward direction. This forward and backward movement is performed repeatedly by the Robot.
Your task is to calculate amount of time taken, before the Robot falls in either ditch, if at all it falls in a ditch. - 9 years agoHelpfull: Yes(0) No(1)
- #include
int main()
{
int n,f,b,tot,fd,bd;
int t;
scanf("%d",&n);
if (n>0 && n0 && b>0 && tot>0 && fd>0 && bd>0)
{
t=0;
if(f==b||f>fd)
{
if(f>=fd)
{
t=fd*tot;
printf("%d F",t);
}
else
printf("No Ditch");
}
else if(f>b)
{
while(fd>0)
{
fd-=f;
//printf("ntest fd=%dn",fd);
t+=f;
if(fd>0)
{
fd+=b;
t+=b;
}
}
t+=fd;
t*=tot;
printf("%d F",t);
}
else if(f0)
{
bd-=b;
//printf("ntest bd=%dn",bd);
t+=b;
//printf("ntest t=%dn",t);
if(bd>0)
{
bd+=f;
t+=f;
}
}
t+=bd;
t*=tot;
printf("%d B",t);
}
printf("n");
}
}
return 0;
}
} - 9 years agoHelpfull: Yes(0) No(4)
TCS Other Question
3 persons a,b,c were there A always says truth,B lies on Monday,tusday,&
Wednesday.but C lies on thrusday,Friday & saturday .one day A said”that B & C said to A
that” B said “yesterday way one of the days when I lies”,C said that”yesterday way one of
the days when I lies too”.then which day was that?
A Milkman serves milk in packaged bottles of varied sizes. The possible size of the bottles are {1, 5, 7 and 10} litres. He wants to supply desired quantity using as less bottles as possible irrespective of the size. Your objective is to help him find the minimum number of bottles required to supply the given demand of milk.
Input Format:
First line contains number of test cases N
Next N lines, each contain a positive integer Li which corresponds to the demand of milk.
Output Format:
For each input Li, print the minimum number of bottles required to fulfill the demand
Constraints:
1 <= N <= 1000
Li > 0
1 <= i <= N
Sample Input and Output
SNo. Input Output
1
2
17
65
2
7
Explanation:
Number of test cases is 2
In first test case, demand of milk is 17 litres which can be supplied using minimum of 2 bottles as follows
1 x 10 litres and
1 x 7 litres
In second test case, demand of milk is 65 litres which can be supplied using minimum of 7 bottles as follows
6 x 10 litres and
1 x 5 litres