Campus
Maths Puzzle
Numerical Ability
the average age of the family of 5 members is 20years.if the age of the youngest member be 10 years then what was the average age of the family at the time of the birth of youngest member
Read Solution (Total 4)
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- Average age of 5 Persons is 20 yrs.
Therefore, Age of 1 persons is 20*5
- 9 years agoHelpfull: Yes(0) No(0)
- Average age of 5 Persons is 20 yrs.
Therefore, Age of 1 persons is 20*5
= 100
Age of youngest member is 10 yrs.
Therefore, At his birth 4x= 100-10
4x= 90
x=22.5 yrs.
Average Age is 22.5 yrs. - 9 years agoHelpfull: Yes(0) No(1)
- (4x+10) / 5 = 20
therefore
4x + 10 = 100
-> 4x = 90
now
4x / 4 = ?
therefore answer is 90/4 = 22.5 - 9 years agoHelpfull: Yes(0) No(1)
- Total age of the five members=5*20=100 years
age of the youngest person=10 years
Total age of the remaining 4 members=90 years
Hence at the time of the birth of youngest person ,avg age of the family= [90-(4*10)]/4 = 12.5 years.
- 8 years agoHelpfull: Yes(0) No(0)
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