find da maximum value of n such that 570*60*30*90*100*500*700*343*720*81 is perfectly divisible by 30^n answer

• n=4
  since after multipliying we get 8 zeroes
• 8 years agoHelpfull: Yes(0) No(1)
• 8
  no of zeroes in this is 11 and no of multiple of 3 is 8 so 8 is the correct
• 8 years agoHelpfull: Yes(0) No(2)
• factors of 30=2,3,5....in this 2 is more frequently occuring so .. we will only calculate no of 3 and 5 present in the sequence...
  no 5 3
  ------------------
  570 1 1
  60 1 1
  30 1 1
  90 1 2
  100 2 0
  500 3 0
  700 2 0
  343 0 0
  720 1 2
  81 0 4
  ------------------------
  total 12 11
  so n=11
• 8 years agoHelpfull: Yes(0) No(0)
• 11 no. of zeros and 11 no. of 3 is here.
  so n=11
• 8 years agoHelpfull: Yes(0) No(0)